map
for Result
Panicking in the previous example's multiply
does not make for robust code.
Generally, we want to return the error to the caller so it can decide what is
the right way to respond to errors.
We first need to know what kind of error type we are dealing with. To determine
the Err
type, we look to parse()
, which is implemented with the
FromStr
trait for i32
. As a result, the Err
type is
specified as ParseIntError
.
In the example below, the straightforward match
statement leads to code
that is overall more cumbersome.
use std::num::ParseIntError; // With the return type rewritten, we use pattern matching without `unwrap()`. fn multiply(first_number_str: &str, second_number_str: &str) -> Result<i32, ParseIntError> { match first_number_str.parse::<i32>() { Ok(first_number) => { match second_number_str.parse::<i32>() { Ok(second_number) => { Ok(first_number * second_number) }, Err(e) => Err(e), } }, Err(e) => Err(e), } } fn print(result: Result<i32, ParseIntError>) { match result { Ok(n) => println!("n is {}", n), Err(e) => println!("Error: {}", e), } } fn main() { // This still presents a reasonable answer. let twenty = multiply("10", "2"); print(twenty); // The following now provides a much more helpful error message. let tt = multiply("t", "2"); print(tt); }
Luckily, Option
's map
, and_then
, and many other combinators are also
implemented for Result
. Result
contains a complete listing.
use std::num::ParseIntError; // As with `Option`, we can use combinators such as `map()`. // This function is otherwise identical to the one above and reads: // Multiply if both values can be parsed from str, otherwise pass on the error. fn multiply(first_number_str: &str, second_number_str: &str) -> Result<i32, ParseIntError> { first_number_str.parse::<i32>().and_then(|first_number| { second_number_str.parse::<i32>().map(|second_number| first_number * second_number) }) } fn print(result: Result<i32, ParseIntError>) { match result { Ok(n) => println!("n is {}", n), Err(e) => println!("Error: {}", e), } } fn main() { // This still presents a reasonable answer. let twenty = multiply("10", "2"); print(twenty); // The following now provides a much more helpful error message. let tt = multiply("t", "2"); print(tt); }