Struct std::collections::BinaryHeap
1.0.0 · source · pub struct BinaryHeap<T> { /* private fields */ }
Expand description
A priority queue implemented with a binary heap.
This will be a max-heap.
It is a logic error for an item to be modified in such a way that the
item’s ordering relative to any other item, as determined by the Ord
trait, changes while it is in the heap. This is normally only possible
through interior mutability, global state, I/O, or unsafe code. The
behavior resulting from such a logic error is not specified, but will
be encapsulated to the BinaryHeap
that observed the logic error and not
result in undefined behavior. This could include panics, incorrect results,
aborts, memory leaks, and non-termination.
As long as no elements change their relative order while being in the heap
as described above, the API of BinaryHeap
guarantees that the heap
invariant remains intact i.e. its methods all behave as documented. For
example if a method is documented as iterating in sorted order, that’s
guaranteed to work as long as elements in the heap have not changed order,
even in the presence of closures getting unwinded out of, iterators getting
leaked, and similar foolishness.
Examples
use std::collections::BinaryHeap;
// Type inference lets us omit an explicit type signature (which
// would be `BinaryHeap<i32>` in this example).
let mut heap = BinaryHeap::new();
// We can use peek to look at the next item in the heap. In this case,
// there's no items in there yet so we get None.
assert_eq!(heap.peek(), None);
// Let's add some scores...
heap.push(1);
heap.push(5);
heap.push(2);
// Now peek shows the most important item in the heap.
assert_eq!(heap.peek(), Some(&5));
// We can check the length of a heap.
assert_eq!(heap.len(), 3);
// We can iterate over the items in the heap, although they are returned in
// a random order.
for x in &heap {
println!("{x}");
}
// If we instead pop these scores, they should come back in order.
assert_eq!(heap.pop(), Some(5));
assert_eq!(heap.pop(), Some(2));
assert_eq!(heap.pop(), Some(1));
assert_eq!(heap.pop(), None);
// We can clear the heap of any remaining items.
heap.clear();
// The heap should now be empty.
assert!(heap.is_empty())
RunA BinaryHeap
with a known list of items can be initialized from an array:
use std::collections::BinaryHeap;
let heap = BinaryHeap::from([1, 5, 2]);
RunMin-heap
Either core::cmp::Reverse
or a custom Ord
implementation can be used to
make BinaryHeap
a min-heap. This makes heap.pop()
return the smallest
value instead of the greatest one.
use std::collections::BinaryHeap;
use std::cmp::Reverse;
let mut heap = BinaryHeap::new();
// Wrap values in `Reverse`
heap.push(Reverse(1));
heap.push(Reverse(5));
heap.push(Reverse(2));
// If we pop these scores now, they should come back in the reverse order.
assert_eq!(heap.pop(), Some(Reverse(1)));
assert_eq!(heap.pop(), Some(Reverse(2)));
assert_eq!(heap.pop(), Some(Reverse(5)));
assert_eq!(heap.pop(), None);
RunTime complexity
The value for push
is an expected cost; the method documentation gives a
more detailed analysis.
Implementations§
source§impl<T> BinaryHeap<T>where
T: Ord,
impl<T> BinaryHeap<T>where T: Ord,
sourcepub fn new() -> BinaryHeap<T>
pub fn new() -> BinaryHeap<T>
sourcepub fn with_capacity(capacity: usize) -> BinaryHeap<T>
pub fn with_capacity(capacity: usize) -> BinaryHeap<T>
Creates an empty BinaryHeap
with at least the specified capacity.
The binary heap will be able to hold at least capacity
elements without
reallocating. This method is allowed to allocate for more elements than
capacity
. If capacity
is 0, the binary heap will not allocate.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::with_capacity(10);
heap.push(4);
Run1.12.0 · sourcepub fn peek_mut(&mut self) -> Option<PeekMut<'_, T>>
pub fn peek_mut(&mut self) -> Option<PeekMut<'_, T>>
Returns a mutable reference to the greatest item in the binary heap, or
None
if it is empty.
Note: If the PeekMut
value is leaked, some heap elements might get
leaked along with it, but the remaining elements will remain a valid
heap.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::new();
assert!(heap.peek_mut().is_none());
heap.push(1);
heap.push(5);
heap.push(2);
{
let mut val = heap.peek_mut().unwrap();
*val = 0;
}
assert_eq!(heap.peek(), Some(&2));
RunTime complexity
If the item is modified then the worst case time complexity is O(log(n)), otherwise it’s O(1).
sourcepub fn pop(&mut self) -> Option<T>
pub fn pop(&mut self) -> Option<T>
Removes the greatest item from the binary heap and returns it, or None
if it
is empty.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::from([1, 3]);
assert_eq!(heap.pop(), Some(3));
assert_eq!(heap.pop(), Some(1));
assert_eq!(heap.pop(), None);
RunTime complexity
The worst case cost of pop
on a heap containing n elements is O(log(n)).
sourcepub fn push(&mut self, item: T)
pub fn push(&mut self, item: T)
Pushes an item onto the binary heap.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::new();
heap.push(3);
heap.push(5);
heap.push(1);
assert_eq!(heap.len(), 3);
assert_eq!(heap.peek(), Some(&5));
RunTime complexity
The expected cost of push
, averaged over every possible ordering of
the elements being pushed, and over a sufficiently large number of
pushes, is O(1). This is the most meaningful cost metric when pushing
elements that are not already in any sorted pattern.
The time complexity degrades if elements are pushed in predominantly ascending order. In the worst case, elements are pushed in ascending sorted order and the amortized cost per push is O(log(n)) against a heap containing n elements.
The worst case cost of a single call to push
is O(n). The worst case
occurs when capacity is exhausted and needs a resize. The resize cost
has been amortized in the previous figures.
1.5.0 · sourcepub fn into_sorted_vec(self) -> Vec<T, Global>
pub fn into_sorted_vec(self) -> Vec<T, Global>
1.11.0 · sourcepub fn append(&mut self, other: &mut BinaryHeap<T>)
pub fn append(&mut self, other: &mut BinaryHeap<T>)
Moves all the elements of other
into self
, leaving other
empty.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut a = BinaryHeap::from([-10, 1, 2, 3, 3]);
let mut b = BinaryHeap::from([-20, 5, 43]);
a.append(&mut b);
assert_eq!(a.into_sorted_vec(), [-20, -10, 1, 2, 3, 3, 5, 43]);
assert!(b.is_empty());
Runsourcepub fn drain_sorted(&mut self) -> DrainSorted<'_, T> ⓘ
🔬This is a nightly-only experimental API. (binary_heap_drain_sorted
#59278)
pub fn drain_sorted(&mut self) -> DrainSorted<'_, T> ⓘ
binary_heap_drain_sorted
#59278)Clears the binary heap, returning an iterator over the removed elements in heap order. If the iterator is dropped before being fully consumed, it drops the remaining elements in heap order.
The returned iterator keeps a mutable borrow on the heap to optimize its implementation.
Note:
.drain_sorted()
is O(n * log(n)); much slower than.drain()
. You should use the latter for most cases.
Examples
Basic usage:
#![feature(binary_heap_drain_sorted)]
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::from([1, 2, 3, 4, 5]);
assert_eq!(heap.len(), 5);
drop(heap.drain_sorted()); // removes all elements in heap order
assert_eq!(heap.len(), 0);
Run1.70.0 · sourcepub fn retain<F>(&mut self, f: F)where
F: FnMut(&T) -> bool,
pub fn retain<F>(&mut self, f: F)where F: FnMut(&T) -> bool,
Retains only the elements specified by the predicate.
In other words, remove all elements e
for which f(&e)
returns
false
. The elements are visited in unsorted (and unspecified) order.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::from([-10, -5, 1, 2, 4, 13]);
heap.retain(|x| x % 2 == 0); // only keep even numbers
assert_eq!(heap.into_sorted_vec(), [-10, 2, 4])
Runsource§impl<T> BinaryHeap<T>
impl<T> BinaryHeap<T>
sourcepub fn into_iter_sorted(self) -> IntoIterSorted<T> ⓘ
🔬This is a nightly-only experimental API. (binary_heap_into_iter_sorted
#59278)
pub fn into_iter_sorted(self) -> IntoIterSorted<T> ⓘ
binary_heap_into_iter_sorted
#59278)Returns an iterator which retrieves elements in heap order. This method consumes the original heap.
Examples
Basic usage:
#![feature(binary_heap_into_iter_sorted)]
use std::collections::BinaryHeap;
let heap = BinaryHeap::from([1, 2, 3, 4, 5]);
assert_eq!(heap.into_iter_sorted().take(2).collect::<Vec<_>>(), [5, 4]);
Runsourcepub fn peek(&self) -> Option<&T>
pub fn peek(&self) -> Option<&T>
Returns the greatest item in the binary heap, or None
if it is empty.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::new();
assert_eq!(heap.peek(), None);
heap.push(1);
heap.push(5);
heap.push(2);
assert_eq!(heap.peek(), Some(&5));
RunTime complexity
Cost is O(1) in the worst case.
sourcepub fn reserve_exact(&mut self, additional: usize)
pub fn reserve_exact(&mut self, additional: usize)
Reserves the minimum capacity for at least additional
elements more than
the current length. Unlike reserve
, this will not
deliberately over-allocate to speculatively avoid frequent allocations.
After calling reserve_exact
, capacity will be greater than or equal to
self.len() + additional
. Does nothing if the capacity is already
sufficient.
Panics
Panics if the new capacity overflows usize
.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::new();
heap.reserve_exact(100);
assert!(heap.capacity() >= 100);
heap.push(4);
Runsourcepub fn reserve(&mut self, additional: usize)
pub fn reserve(&mut self, additional: usize)
Reserves capacity for at least additional
elements more than the
current length. The allocator may reserve more space to speculatively
avoid frequent allocations. After calling reserve
,
capacity will be greater than or equal to self.len() + additional
.
Does nothing if capacity is already sufficient.
Panics
Panics if the new capacity overflows usize
.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::new();
heap.reserve(100);
assert!(heap.capacity() >= 100);
heap.push(4);
Run1.63.0 · sourcepub fn try_reserve_exact(
&mut self,
additional: usize
) -> Result<(), TryReserveError>
pub fn try_reserve_exact( &mut self, additional: usize ) -> Result<(), TryReserveError>
Tries to reserve the minimum capacity for at least additional
elements
more than the current length. Unlike try_reserve
, this will not
deliberately over-allocate to speculatively avoid frequent allocations.
After calling try_reserve_exact
, capacity will be greater than or
equal to self.len() + additional
if it returns Ok(())
.
Does nothing if the capacity is already sufficient.
Note that the allocator may give the collection more space than it
requests. Therefore, capacity can not be relied upon to be precisely
minimal. Prefer try_reserve
if future insertions are expected.
Errors
If the capacity overflows, or the allocator reports a failure, then an error is returned.
Examples
use std::collections::BinaryHeap;
use std::collections::TryReserveError;
fn find_max_slow(data: &[u32]) -> Result<Option<u32>, TryReserveError> {
let mut heap = BinaryHeap::new();
// Pre-reserve the memory, exiting if we can't
heap.try_reserve_exact(data.len())?;
// Now we know this can't OOM in the middle of our complex work
heap.extend(data.iter());
Ok(heap.pop())
}
Run1.63.0 · sourcepub fn try_reserve(&mut self, additional: usize) -> Result<(), TryReserveError>
pub fn try_reserve(&mut self, additional: usize) -> Result<(), TryReserveError>
Tries to reserve capacity for at least additional
elements more than the
current length. The allocator may reserve more space to speculatively
avoid frequent allocations. After calling try_reserve
, capacity will be
greater than or equal to self.len() + additional
if it returns
Ok(())
. Does nothing if capacity is already sufficient. This method
preserves the contents even if an error occurs.
Errors
If the capacity overflows, or the allocator reports a failure, then an error is returned.
Examples
use std::collections::BinaryHeap;
use std::collections::TryReserveError;
fn find_max_slow(data: &[u32]) -> Result<Option<u32>, TryReserveError> {
let mut heap = BinaryHeap::new();
// Pre-reserve the memory, exiting if we can't
heap.try_reserve(data.len())?;
// Now we know this can't OOM in the middle of our complex work
heap.extend(data.iter());
Ok(heap.pop())
}
Runsourcepub fn shrink_to_fit(&mut self)
pub fn shrink_to_fit(&mut self)
1.56.0 · sourcepub fn shrink_to(&mut self, min_capacity: usize)
pub fn shrink_to(&mut self, min_capacity: usize)
Discards capacity with a lower bound.
The capacity will remain at least as large as both the length and the supplied value.
If the current capacity is less than the lower limit, this is a no-op.
Examples
use std::collections::BinaryHeap;
let mut heap: BinaryHeap<i32> = BinaryHeap::with_capacity(100);
assert!(heap.capacity() >= 100);
heap.shrink_to(10);
assert!(heap.capacity() >= 10);
Runsourcepub fn as_slice(&self) -> &[T]
🔬This is a nightly-only experimental API. (binary_heap_as_slice
#83659)
pub fn as_slice(&self) -> &[T]
binary_heap_as_slice
#83659)1.6.0 · sourcepub fn drain(&mut self) -> Drain<'_, T> ⓘ
pub fn drain(&mut self) -> Drain<'_, T> ⓘ
Clears the binary heap, returning an iterator over the removed elements in arbitrary order. If the iterator is dropped before being fully consumed, it drops the remaining elements in arbitrary order.
The returned iterator keeps a mutable borrow on the heap to optimize its implementation.
Examples
Basic usage:
use std::collections::BinaryHeap;
let mut heap = BinaryHeap::from([1, 3]);
assert!(!heap.is_empty());
for x in heap.drain() {
println!("{x}");
}
assert!(heap.is_empty());
RunTrait Implementations§
source§impl<T> Clone for BinaryHeap<T>where
T: Clone,
impl<T> Clone for BinaryHeap<T>where T: Clone,
source§fn clone(&self) -> BinaryHeap<T>
fn clone(&self) -> BinaryHeap<T>
source§fn clone_from(&mut self, source: &BinaryHeap<T>)
fn clone_from(&mut self, source: &BinaryHeap<T>)
source
. Read more1.4.0 · source§impl<T> Debug for BinaryHeap<T>where
T: Debug,
impl<T> Debug for BinaryHeap<T>where T: Debug,
source§impl<T> Default for BinaryHeap<T>where
T: Ord,
impl<T> Default for BinaryHeap<T>where T: Ord,
source§fn default() -> BinaryHeap<T>
fn default() -> BinaryHeap<T>
Creates an empty BinaryHeap<T>
.
1.2.0 · source§impl<'a, T> Extend<&'a T> for BinaryHeap<T>where
T: 'a + Ord + Copy,
impl<'a, T> Extend<&'a T> for BinaryHeap<T>where T: 'a + Ord + Copy,
source§impl<T> Extend<T> for BinaryHeap<T>where
T: Ord,
impl<T> Extend<T> for BinaryHeap<T>where T: Ord,
source§fn extend<I>(&mut self, iter: I)where
I: IntoIterator<Item = T>,
fn extend<I>(&mut self, iter: I)where I: IntoIterator<Item = T>,
source§fn extend_one(&mut self, item: T)
fn extend_one(&mut self, item: T)
extend_one
#72631)source§impl<T> FromIterator<T> for BinaryHeap<T>where
T: Ord,
impl<T> FromIterator<T> for BinaryHeap<T>where T: Ord,
source§fn from_iter<I>(iter: I) -> BinaryHeap<T>where
I: IntoIterator<Item = T>,
fn from_iter<I>(iter: I) -> BinaryHeap<T>where I: IntoIterator<Item = T>,
source§impl<'a, T> IntoIterator for &'a BinaryHeap<T>
impl<'a, T> IntoIterator for &'a BinaryHeap<T>
source§impl<T> IntoIterator for BinaryHeap<T>
impl<T> IntoIterator for BinaryHeap<T>
source§fn into_iter(self) -> IntoIter<T> ⓘ
fn into_iter(self) -> IntoIter<T> ⓘ
Creates a consuming iterator, that is, one that moves each value out of the binary heap in arbitrary order. The binary heap cannot be used after calling this.
Examples
Basic usage:
use std::collections::BinaryHeap;
let heap = BinaryHeap::from([1, 2, 3, 4]);
// Print 1, 2, 3, 4 in arbitrary order
for x in heap.into_iter() {
// x has type i32, not &i32
println!("{x}");
}
Run